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    Fizzbuzz without ifs in 90 char. I will buy you a beer if you can do better.

    Yesterday I got nerd sniped into solving the FizzBuzz problem without using if sentences.https://twitter.com/Swizec/status/247344854521245697

    Unfortunately, a more careful inspection of the problem specification reveals this solution was incorrect.

    Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz".

    Luckily, that's a very simple fix:

    # codegolf version (90 characters):
    [{0:"fizzbuzz"}.get(x%(3*5),{0:"fizz"}.get(x%3,{0:"buzz"}.get(x%5,x)))for x in range(101)]
    # slightly more readable:
    [{0: "fizzbuzz"}.get(x%(3*5),
    {0: "fizz"}.get(x%3,
    {0: "buzz"}.get(x%5, x)))
    for x in range(101)]

    There you have it, a solution to the fizzbuzz problem that relies on python's interactive command line interpreter thingy to do the printing, so it shave off 4 characters for print.

    The "trick", if it can be called that, is relying on the native get method to return the correct string or fall back to the default value, which checks for the next string in the if-then-else chain.

    I wish never to see code like that in something I have to maintain. Ever :)

    The challenge

    Your challenge, should you choose to accept it, is to produce a shorter fizzbuzz solution without using if sentences. I will buy a bottle of beer for the winner.

    The best Scala solution so far is 106 characters. https://twitter.com/HairyFotr/status/247362763188477953

    No really, I will send a bottle of beer anywhere in the world if you write a shorter solution. Of course, if feasible, I would prefer to take you out for a beer than use snail mail :)

    Beer bottles by photos for fun
    Beer bottles by photos for fun

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    Published on September 17th, 2012 in Uncategorized

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