The problem I'm trying to solve is the simple but lovely euler 62.

The cube, 41063625 (3453), can be permuted to produce two other cubes: 56623104 (3843) and 66430125 (4053). In fact, 41063625 is the smallest cube which has exactly three permutations of its digits which are also cube.

Find the smallest cube for which exactly five permutations of its digits are cube.

A bit of fun coding after a statistics midterm last night and the solution should be in the bag. Except it isn't, I am doing something wrong somehow and I can't figure out what! Hopefully someone a bit better than me can shed some light whether my proposed solution is wrong or I just suck at Haskell.

## Algorithm

- Generate cubes up to 10,000
- Every cube is a pair of a digit-ordered string
*n^3*and*n, _for instance*("279",9)_ - Order cubes by the string number presentation
- Group together all cubes with the same
*n^3* - Pick out groups with the size of 5
- Sort by
*n* - Pick the smallest number

Should work in principle right? So why doesn't the website accept my answer *(5027)*? My guess is I'm doing something wrong in the sorting and grouping department and I was hoping someone with a bit more knowledge of Haskell could point out where I'm being stupid.

## Code

import Data.Listcubes::(Num a) => a -> [(String, a)]cubes 1 = [(show 1, 1)]cubes n = (sort$show(n^3), n):(cubes $ n-1)sortStrNum (s1, n1) (s2, n2)| length s1 == length s2 = compare s1 s2| otherwise = compare (length s1) (length s2)permuted_cubes n =groupBy (\a b -> fst a == fst b) $ sortBy sortStrNum $ cubes nfives n =filter (\xs -> length xs == 5) $ permuted_cubes ncomparing p x y = compare (p x) (p y)smallest =head $ sortBy (comparing snd) $ head $ fives 100000

The whole thing looks kind of alright to me, no matter how much I poke around it doesn't seem like something is misbehaving ... but it still is.

Ideas?

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